Any or All

_any()

This expression returns True if any element of the iterable is true.
If the iterable is empty, it will return False.

_Code

>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False

_all()

This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.

_Code

>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False

Task

You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.

Input Format

The first line contains an integer N. N is the total number of integers in the list.
The second line contains the space separated list of N integers.

Constraints

0 < N < 100

Output Format

Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

Sample Input

5
12 9 61 5 14 

Sample Output

True

Explanation

Condition 1: All the integers in the list are positive.
Condition 2: 5 is a palindromic integer.

Hence, the output is True.

Can you solve this challenge in 3 lines of code or less?
There is no penalty for solutions that are correct but have more than 3 lines.

Solution Implementation

N = int(input())
numbers = list(map(int, input().split()))
print(all([x > 0 for x in numbers]) and any([str(x) == str(x)[::-1] for x in numbers]))
    # My best attempt at an under 3-line solution.