Java Datatypes

Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we’ll work with the primitives used to hold integer values (byte, short, int, and long):

• A byte is an 8-bit signed integer.
• A short is a 16-bit signed integer.
• An int is a 32-bit signed integer.
• A long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.

Reference: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Input Format

The first line contains an integer ,T , denoting the number of test cases.
Each test case, T, is comprised of a single line with an integer, n, which can be arbitrarily large or small.

Output Format

For each input variable n and appropriate primitive datatype, you must determine if the given primitives are capable of storing it. If yes, then print:

n can be fitted in:
* dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.: byte < short < int <long). ).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

n can't be fitted anywhere.

Sample Input

5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000

Sample Output

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long

Explanation

 -150 can be stored in a short, an int, or a long.

 213333333333333333333333333333333333 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

Solution Implementation

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class JavaDatatypes {
    static String whoCanFitTheNumber(String numString)
    {
        String answer = "";
        try{
            long num = Long.parseLong(numString);
            answer = numString + " can be fitted in:\n";
            if((num<=Byte.MAX_VALUE) && (num>=Byte.MIN_VALUE)){
                answer = answer.concat("* byte\n* short\n* int\n* long");
            }else if((num <= Short.MAX_VALUE) && (num >= Short.MIN_VALUE)){
                answer = answer.concat("* short\n* int\n* long");
            }else if((num <= Integer.MAX_VALUE) && (num >= Integer.MIN_VALUE)){
                    answer = answer.concat("* int\n* long");
            }else{
                    answer = answer.concat("* long");
            }
        }catch (NumberFormatException e){
            answer = numString+" can't be fitted anywhere.";
        }
        return answer;
    }
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int numTestCases = scanner.nextInt() ;
        scanner.nextLine();
        for(int i=0; i<numTestCases;i++){
            String numString = scanner.nextLine();
            System.out.println(whoCanFitTheNumber(numString));
        }
    }
}