Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution. (Wikipedia)
Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.
This problem will test your knowledge on try-catch block.
You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if y is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.
Sample Input 0:
10
3
Sample Output 0:
3
Sample Input 1:
10
Hello
Sample Output 1:
java.util.InputMismatchException
Sample Input 2:
10
0
Sample Output 2:
java.lang.ArithmeticException: / by zero
Sample Input 3:
23.323
0
Sample Output 3:
java.util.InputMismatchException
Solution Implementation
import java.io.*;
import java.util.*;
public class Solution {
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
try{
Scanner sc = new Scanner(System.in);
int a = sc.nextInt();
int b = sc.nextInt();
int c = a/b;
System.out.print(c);
}
catch(InputMismatchException ob){
System.out.print("java.util.InputMismatchException");
}
catch(Exception e)
{
System.out.print(e);
}
}
}

Very good👍