You are given a table, BST, containing two columns: N and P, where N represents the value of a node in Binary Tree, and P is the parent of N.

Write a query to find the node type of Binary Tree ordered by the value of the node. Output one of the following for each node:
- Root: If node is root node.
- Leaf: If node is leaf node.
- Inner: If node is neither root nor leaf node.
Sample Input

Sample Output
1 Leaf
2 Inner
3 Leaf
5 Root
6 Leaf
8 Inner
9 Leaf
Explanation
The Binary Tree below illustrates the sample:

Solution Implementation
select N,
case when P is null then 'Root'
when (select count(*) from BST where P = B.N) > 0 then
'Inner'
else 'Leaf'
end
from BST as B
order by N
;
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