The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.
Example
marks key:value pairs are
‘alpha’: [20, 30, 40]
‘beta’: [30,50,70]
query_name = ‘beta’
The query_name is ‘beta’. beta’s average score is (30+50+70)/3 = 50.0.
Input Format
The first line contains the integer n, the number of students’ records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.
Constraints
- 2 ≤ n ≤ 10
- 0 ≤ makes[i] ≤ 100
- length of marks arrays = 3
Output Format
Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.
Sample Input 0
3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika
Sample Output 0
56.00
Explanation 0
Marks for Malika are {52, 56, 60} whose average is (52+56+60)/3 ⇒ 56
Sample Input 1
2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh
Sample Output 1
26.50
Solution Implementation
"""
Finding the percentage
https://www.hackerrank.com/challenges/finding-the-percentage/problem
"""
if __name__ == '__main__':
n = int(input())
student_marks = {}
for _ in range(n):
name, *line = input().split()
scores = list(map(float, line))
student_marks[name] = scores
query_name = input()
print("%.02f" % (sum(student_marks[query_name]) / 3))