Java If-Else

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

_{Source: Wikipedia}

Task
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

• 1 ≤ n ≤ 100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: n = 3
 n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n=24
 n>20 and n is even, so it isn’t weird. Thus, we print Not Weird.

Solution Implementation

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";
        if(n%2==1){
          ans = "Weird";
        }
        else {
            if (n >= 2 && n <= 5) {
                ans = "Not Weird";
            } else if (n >= 6 && n <= 20) {
                ans = "Weird";
            } else {
                ans = "Not Weird";
            }
        }
        System.out.println(ans);
        
    }
}