start() & end()
These expressions return the indices of the start and end of the substring matched by the group.
Code
>>> import re
>>> m = re.search(r'\d+','1234')
>>> m.end()
4
>>> m.start()
0
Task
You are given a string S.
Your task is to find the indices of the start and end of string k in S.
Input Format
The first line contains the string S.
The second line contains the string k.
Constraints
0 < len(S) < 100
0 < len(k) < len(S)
Output Format
Print the tuple in this format: (start _index, end _index).
If no match is found, print (-1, -1)
.
Sample Input
aaadaa
aa
Sample Output
(0, 1)
(1, 2)
(4, 5)
Solution Implementation
import re
string = input()
substring = input()
pattern = re.compile(substring)
match = pattern.search(string)
if not match: print('(-1, -1)')
while match:
print('({0}, {1})'.format(match.start(), match.end() - 1))
match = pattern.search(string, match.start() + 1)
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