In a tag-based language like XML or HTML, contents are enclosed between a start tag and an end tag like <tag>contents</tag>
. Note that the corresponding end tag starts with a /
.
Given a string of text in a tag-based language, parse this text and retrieve the contents enclosed within sequences of well-organized tags meeting the following criterion:
- The name of the start and end tags must be same. The HTML code
<h1>Hello World</h2>
is not valid, because the text starts with anh1
tag and ends with a non-matchingh2
tag. - Tags can be nested, but content between nested tags is considered not valid. For example, in
<h1><a>contents</a>invalid</h1>
,contents
is valid butinvalid
is not valid. - Tags can consist of any printable characters.
Input Format
The first line of input contains a single integer, N (the number of lines).
The N subsequent lines each contain a line of text.
Constraints
- 1 ≤ N ≤ 100
- Each line contains a maximum of printable characters.
- The total number of characters in all test cases will not exceed 106.
Output Format
For each line, print the content enclosed within valid tags.
If a line contains multiple instances of valid content, print out each instance of valid content on a new line; if no valid content is found, print None
.
Sample Input
4
<h1>Nayeem loves counseling</h1>
<h1><h1>Sanjay has no watch</h1></h1><par>So wait for a while</par>
<Amee>safat codes like a ninja</amee>
<SA premium>Imtiaz has a secret crush</SA premium>
Sample Output
Nayeem loves counseling
Sanjay has no watch
So wait for a while
None
Imtiaz has a secret crush
Solution Implementation
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class TagContentExtractor{
public static void main(String[] args){
Scanner in = new Scanner(System.in);
int testCases = Integer.parseInt(in.nextLine());
String regexPatern = "(<[^>]*>)";
Pattern stringPatern = Pattern.compile(regexPatern);
while(testCases>0){
String line = in.nextLine();
int pos = 0;
Matcher m = stringPatern.matcher(line);
String previousHTMLTag = null;
int previousTagPos = -1;
boolean didFind = false;
while(m.find())
{
String htmlTag = line.substring(m.start(),m.end());
if(htmlTag.charAt(1) != '/')
{
previousHTMLTag = htmlTag;
previousTagPos = m.end();
}else if(htmlTag.charAt(1) == '/' && previousHTMLTag != null){
if(previousHTMLTag.substring(1).equals(htmlTag.substring(2))&&previousHTMLTag.length()>2 && m.start()>previousTagPos+1){
System.out.println(line.substring(previousTagPos,m.start()));
didFind = true;
}
previousHTMLTag = null;
}
}
System.out.print(didFind?"":"None\n");
testCases--;
}
}
}